The basic law of a motor, the reason why they rotate, is governed by Fleming’s left hand rule (see figure below). This tells you the direction of the force on a wire that is carrying current when it is in a magnetic field.
The next diagram shows the force acting on a wire carrying current, obeying the left hand rule:
If we now bend the wire round in a loop, and place it in a magnetic field caused by two permanent magnets, we have the situation shown in the diagram below. Here, both sides of the wire loop will have a force on them, trying to make the wire loop rotate. The current is applied to the loop through the commutator, which is shown as two pieces of metal formed into a ring in the figure. Current is applied to the commutator by stationary graphite blocks, called brushes, which rub against the commutator ring.
The loop will continue to rotate anticlockwise (as we see it in the figure) until it is vertical. At this point, the stationary brushes won't be applying current around the loop any more because they will be contacting the gap between the commutator segments, but the inertia of the loop keeps it going a little more, until the DC supply reconnects to the commutator segments, and the current then goes around the loop in the opposite direction. The force though is still in the same direction, and the loop continues to rotate.
This is how DC motors work. In a real motor, there are many wire loops (windings) all at varying angles around a solid iron core. Each loop has its own pair of commutator segments.This block of core and wire loops is called the rotor because it rotates, or the armature.
The fixed magnets in the diagram above generating the field may be replaced by electromagnets which are generally more powerful. The elctromagnets are supplied by the same power supply as the armature winding, either in series (series connected) or in parallel (shunt connected) as shown in the diagram below.
If permanent magnets are used, the motor is said to be a permanent magnet (PM) motor. DC motors can also have permanent magnets in the armature, and electromagnets for the stator coils. In this case, the stator windings must be switched in some way to make the permanent magnets in the rotor follow them to cause rotation. This connection is less common for small motors.
There may be more than just the two fixed magnets, called poles. In some motors there may be four poles (imagine one more coming from above and one more from below in the figure). There will always be an even number of poles, since there is an N pole for every S pole, and in the equations governing the motor, the number of poles is often quoted as p, the number of pole pairs. These magnets are called the stator because they are stationary, and the electromagnet coils are called the field windings because they generate the magnetic field.
The supply is connected to the commutator segments through graphite brushes. These are held in little sockets with a spring behind them, so the brush is pushed onto the segments. This guarantees a good electrical connection (although there will be a fraction of an Ohm resistance across them). Eventually, these brushes wear down completely. If you get the motors from a scrap yard, the brushes may need replacing. New brushes should be available from automotive spares shops.
A four pole motor is shown in the diagram below. This shows how the magnetic field is generated by the poles and flows through the rotor:
If you can imagine getting the cylindrical rotor of a starter motor, and unrolling it, the wires would look something like this:
In this diagram, the stator magnetic poles are shown underneath the rotor wires. You can trace the electrical current from the supply, through a commutator segment, through all the rotor wire loops, and back through a commutator segment. For a four pole motor (two pairs of poles), two pairs of commutator segments will be supplying current to the rotor wire loops
We can now draw a circuit diagram of the motor. The coils of wire will have a small resistance, and a quite large inductance. Rb represents the resistance through the brushes to the commutator. Rf is the resistance of the field windings, and Ra is the resistance of the armature (rotor) windings.
If the motor is has permanent magnets for the field, then of course Rb and Rf don't exist. Most starter motors use a serial connection. (For example values of these resistances and inductance, the starter motors I am using (from a Ford Fiesta) have an inductance, La, of 71μH, and resistances of Rb=0.008 Ohms, Rf=0.016 Ohms, and Ra=0.017 Ohms, giving a total, Rt, of 0.041 Ohms.
The resistance of the coils of wire that make up the field and armature are normally very low. So you would think that the motor would take a very large current (current = voltage ÷ resistance). However this back emf means that there is actually only a small voltage across the resistance of the coils, because the back emf, ea, is nearly as large as the supply voltage, Vt. Therefore , the actual current taken is
Some typical values for a 900Watt starter motor are: Rt = 0.041 Ohms, Vt = 12V, ea = 11.9v, so the motor current is 2.4 Amps.
The back emf is dependant on the speed of the motor, and is given by the equation
where k is a constant for the motor,Ω m is the speed of the motor, and Φ is the strength of the magnetic field generated by the field coils or magnets. From this equation you can see that when the motor starts, and its speed is zero, then the back emf will be zero, and so the current taken by the motor will be very large. This is also true when the motor is stalled.
When a load is put on the motor, the speed drops, and so the back emf
drops, and so the current drawn from the battery will increase.
The torque produced by a series motor is given by the equation
where kf is a constant for the motor, and ia is the current, and Φ is the field strength. A series wound motor generates its field from the same armature current, so Φ increases as the motor draws current. Therefore the torque is proportional to the square of the current. This means that doubling the current that we put through a series wound motor quadruples the torque. This is a distinct advantage of series wound motors.
For a permanent magnet or shunt wound DC motor, the current drawn by
the motor increases linearly with load torque:
Notice that the line does not intersect the (0Nm / 0A) origin point. The zero torque point intersects at 25 Amps for this motor (an Iskra 900W starter motor). This means that the motor will not even start to turn until it is pulling 25 Amps!
The values Ra and kf are constant for any particular motor. It can be seen that the speed will drop off as the load torque increases, but differently for each type of motor:
From this graph, and the equation, it can be seen that the speed of a series motor with no load torque will rise to infinity! This doesn't happen in practice because there is always a little load torque because due to friction in the motor. It can also be seen that as a little load torque is added to a series wound motor, the speed drops off very quickly to start with, but then drops off less quickly.
With both motor field types, eventually, when the load torque becomes even larger, say when a stronger robot is pushing us backwards, the motor speed becomes negative (the motor starts rotating backwards).
In practice, the speed line for a PM or shunt wound motor may not be a straight due to frictional loads which are not linearly dependant on speed.
The torque speed graph of a DC motor when it is being driven by a speed controller with current limiting can be found in the speed controllers section.
The power the motor is putting into the load is
When the motor is running with no extra load other than its friction, then the load torque is zero, and so the output power is zero. The input power is small also because the back emf is almost equal to the supply voltage. The only power drawn from the battery is driving the loss torque:
When the motor is driving such a large torque that it has stalled, then the back emf is zero, and the input power is very large:
and the output power is zero because the speed is zero.
At some point in between, the output power is at a maximum. If we plot the product of the torque and speed, we will have the graph for power:
The power versus torque graph is a quadratic curve, with a maximum which the manufacturer specifies as the power rating of the motor. For a starter motor on a small car, this is typically around a kilowatt.
The efficiency of the motor is defined as the amount of mechanical power you are getting out of the motor divided by the amount of electrical input power you are putting in, so:
The efficiency can also be plotted against load torque. Here is the efficiency graph for an Iskra shunt wound starter motor:
Just because the maximum efficiency is at around 1Nm doesn't mean that you have to run the motor at that torque though!
There is a section about the power rating of DC motors in the spinning disks chapter here.
Iskra 12 Volt 900 Watt shunt wound starter motor
Scott 4BB-02488 motor (datasheet)
Scott 4BD-1460 motor datasheet.
The Bosch GPA750 has the following nameplate values:
|Nominal voltage||24 V|
|Nominal power||750 W|
|Nominal current||40 A|
|Nominal speed||3300 rpm|
|Stall torque||11 Nm|
Graphs for other motors, and sometimes the same motors at different voltages can be found at the following sites:
Lynch (LEMCO) motors
To fully test the motor, you will need the following equipment:
Fit the motor into the apparatus as shown. There must be a means of adjusting the height of the motor so that band can be tightened. Start it off with the band stretched slightly tightened (but not too tight). Run the motor, and record the speed it is going at (call this w1). The spring balance should change reading a little (if it doesn’t then the band is not tight enough, so move the motor and wheel downwards a little), record the spring balance reading (call this F1).
Now move the motor and wheel further down (tightening the band further) and repeat. make sure that the speed and spring balance reading have changed appreciably - enough to see the difference, but not so much that it stalls the motor. Record the speed (w2) and spring balance readings (F2) again.
The spring balance reading must be converted to Newtons before we can
use it. The speed must be converted to radians per second also. The following
table will help you do these conversions.
The load torque on the motor in the tests is F × r where F is the force in Newtons read by the spring balance, and r is the radius of the wheel (in metres).
By gradually tightening the band, the shape of the torque-speed graph can be established. For a PM or shunt motor, we already know the graph is almost a straight line, so if we knew the stall torque, and the no-load speed, we can just draw a straight line between them. For series motors, the band must be tightened gradually to obtain several readings so the curve can be plotted.
This apparatus is useful if you need to match more than one motor for your robot. If you have two motors and are running them with open-loop speed control, then if they are not sufficiently matched for torque-speed characteristics, then your robot will tend to swerve when you are trying to drive it in a straight line.
Now power up the motor so it will be forcing the bar downwards onto the scales (make sure you have the direction correct and it won't flip upwards!), and read the scales. Do not keep the motor powered up for long as it will be taking a very large current.
The stall torque can now be calculated:
Tstall = 9.81 x W x L
where W is the weight in kg and L is the length of the bar.
no load speed (rads/sec) ÷ gear reducing ratio × wheel radius - speed loss due to friction
If the no load speed is 200 rads/sec, say, and the speed loss due to friction is 2 metres per second, then the road speed will be 200 ÷ 4 × 0.15 - 2 = 5.5 metres per second, which is about 12 miles per hour.
To measure the speed of the motor, you will need a tachograph or Stroboscope . Projects to build both of these are given in the circuits section of this web site. Click on the names above to go to them.
Rtotal = 0.041Ohms
Ltotal = 200μH
You can build your own low resistance meter. Some circuits are presented here.
This requires two motors. One is the motor under test with its rotor fixed, and one is allowed to run freely. To pass current through the motor under test, simply apply a load to the free running motor (trying to slow it down). As its load increaes, it will take more current, and the voltage drop across our motor under test will increaese. You want as large a current as you can measure with your ammeter, so that the voltage is large enough to measure.
Maplin sell one for £100 (part number LD17T), which also includes all the normal ranges of a DMM. If you do not already have a DMM, it may be worth investing in this one. It also has a frequency measurement range up to 20kHz which would be useful when measuring motor rpm. Note that the other similar cheaper meters to this one in Maplins range do not measure DC current, only AC and so are not suitable.
If you already have a DMM, you can buy a clamp attachment which just plugs into your DMM. These can be quite expensive (well over £100 just for the probe, but CPC supply one (order code IN00710) made by Tenma (model number 72-6174) for £30.
It's impossible to say how much current they will take on average, because it depends completely on what the motor is doing at the time.
An ideal electric motor (this doesn't exist of course but it is what motor manufacturers aim for), will convert 100% of the input electrical power into output mechanical power. This means that if the motor is not required to deliver any mechanical power - for example the vehicle is rolling at constant speed and there's no friction (I did say it's the ideal case!) - then it will draw no electrical power.
The mechanical power output is the load torque, 'T' (how much the vehicle is resisting the motor going round) multiplied by the rotational speed of the motor, 'ω'. The electrical input power is the voltage across the motor, 'V', multiplied by the current drawn by the motor, 'I'. In this ideal situation, the mechanical power equals the electrical power:
Pm = Pe
Tω = VI
Therefore, if the load torque is zero, Pm is zero. The voltage will still be across the motor, so I will be zero - the motor takes no current.
Of course the world is not ideal - there will always be friction in real life - the wheel bearings, any gearing you have, the wheels against the floor, the bearings in the motor itself etc, and so T will never be zero. It follows therefore that 'I' will never be zero either. There will always be a little bit of current required to drive the vehicle even on a flat surface. For starter motors, this can be reasonably large. The problem with starter motors is that they are designed to do a quick dirty job for a few seconds. Their main design consideration is cost - they must be cheap for the car manufacturers. Most do not have proper roller bearings, but use a phosphor bronze sleeve bearing. The shaft of the motor simply rubs against the very hard bronze. This obviously causes a lot more friction that a roller bearing, but the car manuafacturers don't really care about that - it doesn't matter much for them. I have heard that it can take up to 20 Amps just to overcome this friction, although I have not experienced that myself. One alternative which is quite easy and inexpensive if you have welding equipment is to remove the bronze sleeves, and replace them with roller bearings. A roller bearing shouldn't cost any more than £2 (US$3). This should reduce the frictional current to a couple of amps at most.
As for the maximum current that the motor can take, this is governed by the resistance of its coils and brushes inside. Going back to an ideal motor, this would have zero resistance. When this ideal motor is stalled, it will take an infinite current, which will produce an infinite torque, and push whatever blockage is out of the way. In a real motor, the torque it can produce is not infinite, it is limited by the maximum current that can flow through the motor. The maximum current is simply the voltage applied to it divided by the motor's internal resistance... Imax = V / R. This is often called the stall current because it is the current the motor will take when it is not rotating, but full voltage is applied (i.e. it is stalled). A typical small car starter motor may have an internal resistance of 0.04 Ohms, so at 12V the stall current will be 12 / 0.04 = 300 Amps. Using our old equation Tw = VI, this maximum current corresponds to a maximum torque, which is often called the stall torque, and is how hard the motor will twist if you hold the shaft stationary. The motor is not rated to take this current for any length of time. Typically it will be rated for continuous use at about a quarter of this stall current.
In between these two currents, the motor may take any current, which will depend on the mechanical load. When accelerating the vehicle or pushing against an opposing force, it will take more, when decelerating or going downhill, it may take zero current.
Controlling voltage spikes (motor suppression). SGS Thomson Acrobat
Using car windscreen wiper motors